15th term of A.P., x - 7, x - 2, x + 3, ........ is

Answer: Option A

a_n = a + (n - 1) × d
where,
d = x - 2 -x + 7 = 5,
a = x - 7
⇒ a₁₅ = (x - 7) + (15 - 1) × 5
⇒ a₁₅ = (x - 7) + 14 × 5
⇒ a₁₅ = x - 7 + 70
⇒ a₁₅ = x + 63