Q86
40% of incident radiant energy on the surface of a thermally transparent body is reflected back. If the transmissivity of the body be 0.15, then the emissivity of surface is
A.
0.45
AnswerB.
0.55
C.
0.40
D.
0.75
Answer: Option A
Solution
Answer: Option A
Solution:
a + p + T = 1a + 0.40 + 0.15 = 1 (p = 0.40, T = 0.15)
a = 1 - 0.55
a = 0.45