60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio 3 : 2 and alloy B has tin and copper in the ratio 1 : 4, the amount of tin in the new alloy is -

Answer: Option A

Quantity of tin in 60 kg of A
$$\begin{array}{rl}& =\left(60\times \frac{2}{5}\right)\text{kg}\\ & =24\text{kg}\end{array}$$
Quantity of tin in 100 kg of B
$$\begin{array}{rl}& =\left(100\times \frac{1}{5}\right)\text{kg}\\ & =20\text{kg}\end{array}$$
∴ Quantity of tin in the new alloy
= (24 + 20) kg
= 44 kg