93 × 62 ÷ 33 = ?

Answer: Option B

$$\begin{array}{rl}& \frac{9^3\times 6^2}{3^3}\\ & =\frac{{\left(3^2\right)}^3\times {\left(3\times 2\right)}^2}{3^3}\\ & =\frac{3^{\left(3\times 2\right)}\times 3^2\times 2^2}{3^3}\\ & =\frac{3^{\left(6+2\right)}\times 2^2}{3^3}\\ & =3^{\left(8-3\right)}\times 2^2\\ & =3^5\times 2^2\\ & =243\times 4\\ & =972\end{array}$$