A 750 W electric iron is used for 8 hours per day. So the energy consumed in one day by iron is ?

Answer: Option D

To calculate the energy consumed by the electric iron in one day, we can use the formula:
Energy = Power × Time
Given: Power of the electric iron P = 750W Time the electric iron is used per day t = 8hours
First, we need to convert the time from hours to hours: t=8×1=8 hours
Now, we can calculate the energy consumed: Energy=750×8=6000 watt-hours
Since 1 kilowatt-hour (kWh) is equal to 1 unit of electricity, we need to convert the energy from watt-hours to units: Energy in units = $$\frac{6000}{1000}$$ = 6 units
Therefore, the energy consumed in one day by the electric iron is 6 units.