A and B are two alloys in which ratios of gold and copper are 5 : 3 and 5 : 11 respectively. If these equally amount of two alloys are melted and made alloy C. What will be the ratio of gold and copper in alloy C?

Answer: Option C

Ratio of Gold and Copper in Alloy A = 5 : 3
Ratio of Gold and Copper in Alloy B = 5 : 11
Amount of Gold in Alloy A = $$\frac{5}{8}$$
Amount of Gold In Alloy B = $$\frac{5}{16}$$
Amount of Copper in A = $$\frac{3}{8}$$
Amount of Copper in B = $$\frac{11}{16}$$
Amount of Gold In C,
= (Amount of gold in A + Amount of gold in B) = $$\frac{5}{8}$$ + $$\frac{5}{16}$$ = $$\frac{10+5}{16}$$ = $$\frac{15}{16}$$
Amount of Copper in C,
= Amount of Copper in A + Amount of Copper in B = $$\frac{3}{8}$$ + $$\frac{11}{16}$$ = $$\frac{17}{16}$$
So,
Ratio of Gold and Copper in C,
$$=\frac{15}{16}:\frac{17}{16}=15:17$$