A and B can do a work in 262/3 days. B and C together can complete the same work in 48 days, while A and C together can complete the same work in 30 days. How long (in days) will A alone take to complete 60% of the work?

Answer: Option A

Solution

Answer: Option A

Solution:

$$\text{A}=26\frac{2}{3}=\frac{80}{3}$$

2(A + B + C) = 9 + 5 + 8 = 22
(A + B + C) = 11
A = 11 - 5 = 6
60% of total work $$=\frac{60}{100}\times 240=144$$
$$\text{A}=\frac{144}{6}=24\text{ days}$$