Q747
A body of 4.0 kg is lying at rest. Under the action of a constant force, it gains a speed of 5 m/s. The work done by the force will be ________
A.
50 J
AnswerB.
30 J
C.
20 J
D.
40 J
Answer: Option A
Solution
Answer: Option A
Solution:
Work done = 1/2*m*V2=1/2*4*52
= 1/2*4*25
= 2*25
= 50 J