A can complete a certain work in 35 days and B can complete the same work in 15 days. They worked together for 7 days, then B left the work. In how many days will A alone complete 60% of the remaining work?

Answer: Option A

Solution

Answer: Option A

Solution:

7 days work of (A and B) = 7 × 10 = 70
Remaining work = 105 - 70 = 35
60% of remaining work done by A = $$\frac{35\times \frac{3}{5}}{3}$$  = 7 days