A circle is inscribed in a quadrilateral ABCD touching AB, BC, CD and AD at the points P, Q, R and S, respectively, and ∠B = 90°. If AD = 24 cm, AB = 27 cm and DR = 6 cm, then what is the circumference of the circle?

Answer: Option B

Solution

Answer: Option B

Solution:

In $$\square$$ POQB,
PBOQ is a square because
PB = BQ
PB = OQ
So,
BQ = OQ = OP = r
Circumference = 2πr = 2π × 9 = 18π