A circle is inscribed in a triangle ABC. It touches side AB, BC and AC at points R, P and Q, respectively. If AQ = 2.6 cm, PC = 2.7 cm and BR = 3 cm, then the perimeter (in cm) of the triangle ΔABC is:

Answer: Option C

Solution

Answer: Option C

Solution:

Because tangent drawn from a single point are equal.
So perimeter of ABC = (2.6 + 2.7 + 3) × 2 = 16.6