A circus tent is cylindrical up to a height of 3 m and conical above it. If its diameter is 105 m and the slant height of the conical part is 63 m, then the total area of the canvas required to make the tent is ( take = 227 )

Answer: Option A

∴ Radius of cone $$=\frac{105}{2}\text{m}$$
Slant height of cone = 63 m
⇒ Curved surface area of cone
$$\begin{array}{rl}& =\pi rl\\ & =\frac{22}{7}\times \frac{105}{2}\times 63\\ & =10395{\text{m}}^2\end{array}$$
⇒ Radius of cylinder $$=\frac{105}{2}\text{m}$$
Height = 3 m (given)
∴ Curved surface area of cylinder
$$\begin{array}{rl}& =2\pi rh\\ & =2\times \frac{22}{7}\times \frac{105}{2}\times 3\\ & =990{\text{m}}^2\end{array}$$
∴ Total curved area of structure
⇒ Curved area of cone + Curved area of cylinder
= 10395 + 990
= 11385 m²
∴ Total area of canvas = 11385 m²