A dice is rolled twice. What is the probability of getting sum 9?

Answer: Option C

Possible event = 6 × 6 = 36
Favourable outcomes = {(3, 6), {4, 5}, {5, 4}, (6, 3)}
∴ Probability
$$\begin{array}{rl}& =\frac{\text{Favourable}}{\text{total}}\\ & =\frac{4}{36}\\ & =\frac{1}{9}\end{array}$$