Q68
A function y(t), such that y(0) = 1 and y(1) = 3e-1, is a solution of the differential equation d^2 y d t^2 + 2 dy dt + y = 0. Then y(2) is
A function y(t), such that y(0) = 1 and y(1) = 3e-1, is a solution of the differential equation Then y(2) is
A.
5e-1
B.
5e-2
AnswerC.
7e-1
D.
7e-2
Answer: Option B
Solution
Answer: Option B
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