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Aptitude · Q147

Problems On H.C.F And L.C.M

Competitive Exams · Aptitude · question 147

Q147

A number between 1000 and 2000 which when divided by 30, 36 and 80 gives a remainder 11 in each case is = ?

A.
11523
B.
1451
Answer
C.
1641
D.
1712

Answer: Option B

Solution

Answer: Option B
Solution:
LCM of 30, 36, 80 = 720
Number = 720 × K + 11 (K = 2)
Then the number = 720 × 2 + 11
= 1440 + 11
= 1451