A number consists of two digits such that the digit in the ten's plac…

Question

A number consists of two digits such that the digit in the ten's place is less by 2 than the digit in the unit place. Three times the number added to 6/7 times the number obtained by reversing digits equals 108. The sum…

Accepted Answer

Option C. 6. Answer & Solution Answer: Option C Solution: & Let the unit digit & Ten digit = x - 2 & Number : & = 10(x - 2) + x & = 10x - 20 + x & = 11x - 20 New number obtained after reversing the digits & = 10x + x - 2 & = 11x - 2 & According to the question, & 3 ( 11x - 20 ) + 6/7 ( 11x -…

A number consists of two digits such that the digit in the ten's place is less by 2 than the digit in the unit place. Three times the number added to 6/7 times the number obtained by reversing digits equals 108. The sum of digits in the number is -

Solution