A number is successively divided by 8, 7 and 3 giving residues 3, 4 and 2 respectively and quotient 31. The number is :

Answer: Option B

z = 3 × 31 + 2 = 95
y = 7 × z + 4 = 7 × 95 + 4 = 669
x = 8 × y + 3 = 8 × 669 + 3 = 5355
∴ Required number = 5355