A resonant circuit has a lower critical frequency of 7 kHz and an upper critical frequency of 13 kHz. The bandwidth of the circuit is

Answer: Option A

The bandwidth (BW) of a resonant circuit can be calculated using the formula:

$$BW=\text{Upper Critical Frequency}-\text{Lower Critical Frequency}$$

In this case:

Lower Critical Frequency ($$f_1$$) = 7 kHz
Upper Critical Frequency ($$f_2$$) = 13 kHz

Now, we can calculate the bandwidth:

$$BW=f_2-f_1=13\text{kHz}-7\text{kHz}=6\text{kHz}$$

So, the bandwidth of the circuit is 6 kHz.

The correct answer is Option A: 6 kHz.