A robbery was done by a thief at a jewellery shop and he took 2 kg gold. The shop is 1125 m away from a policeman. The thief starts running at x km/h and the policeman starts chasing at 11 km/h at the same time. The policeman caught the thief in 810 sec. What is the distance run by the thief?

Answer: Option B

Solution

Answer: Option B

Solution:

$$\begin{array}{rl}& \Rightarrow \frac{1125}{\left(11-x\right)\frac{5}{18}}=810\\ & \Rightarrow \frac{1125\times 18}{\left(11-x\right)\times 5}=810\\ & \Rightarrow 5=11-x\\ & \Rightarrow x=6\end{array}$$
Distance of thief = 810 × 6 × $$\frac{5}{18}$$ = 1350 m Ans.