A shopkeeper sells guava worth 22 per kg to Anand and Sakshi for Rs. 25 each. He sold Anand 950 g instead of 1 kg. He sold the 'x' gm to Sakshi instead of 1 kg using a defective weight. If he earns a real profit of Rs. 7.76 by selling both, then what is the value of 'x'?

Answer: Option A

Total profit = 7.76
In I^st case, (Anand) instead of 1 kg, he gave 950 gm
So, profit = 50 gm
⇒ 1000 gm = Rs. 22
1 gm = $$\frac{22}{1000}$$
50 gm = $$\frac{1100}{1000}$$  = 1.1
In I^st case, total profit = 3 + 1.1 = Rs. 4.1
So, left profit = 7.76 - 4.1 = Rs. 3.66
In II^nd case, (Sakshi) profit is Rs. 3 as he sold (in Rs. 25) and left Rs. 0.66 is because he sold less of instead of 1000 gm
So, Rs. 22 → 1000 gm
Rs. 1 → $$\frac{1000}{22}$$  × 0.66 = 30 gm
So he sold 970 gm instead of 1000 gm Answer