A solid cube has side 8 cm. It is cut along diagonals of top face to get 4 equal parts. What is the total surface (in cm2) of each part?

Answer: Option A

Total surface area of each part is = 2 × Area of base + Perimeter of base × Height

$$\begin{array}{rl}& =2\times \frac{1}{2}\times 4\sqrt{2}\times 4\sqrt{2}+\left(8+8\sqrt{2}\right)\times 8\\ & =32+64+64\sqrt{2}\\ & =96+64\sqrt{2}\end{array}$$