A string of length 24 cm is bent first into a square and then into a right-angled triangle by keeping one side of the square fixed as its base. Then the area of triangle equals to:

Answer: Option A

Solution

Answer: Option A

Solution:

$$\begin{array}{rl}& \text{Side of square}=\frac{24}{4}=6\\ & \text{Then area of }\Delta ABC=\frac{1}{2}\times 8\times 6=24\text{ c}{\text{m}}^2\end{array}$$