Q105
A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly?
A.
12
B.
16
AnswerC.
24
D.
18
Answer: Option B
Solution
Answer: Option B
Solution:
Let he has solved correctly X no. of sums. Therefore incorrect no. of sums = 2XNow,
X + 2X = 48
3X = 48
X = 16 sums he has done correctly.