Q98
A student is required to answer 6 out of 10 questions divided into two groups each containing 5 questions. He is not permitted to attempt more than 4 from each group. In how many ways can he make the choice?
A.
210
B.
150
C.
100
D.
200
AnswerAnswer: Option D
Solution
Answer: Option D
Solution:
Number of ways of choosing 6 from 10 = 10C6 = 210Number of ways of attempting more than 4 from a group,
= 2 × 5C5 × 5C1
= 10
Required number of ways
= 210 - 10
= 200