A thief steals a car at 2.30 pm and drives it at 60 kmph. The theft is discovered at 3 pm and the owner sets off in another car at 75 kmph. When will he overtake the thief ?

Answer: Option C

Suppose the thief is overtaken x hrs after 2.30 pm
The, distance covered by the thief in x hrs = Distance covered by owner in $$\left(x-\frac{1}{2}\right)$$  hrs
$$\begin{array}{rl}& \therefore 60x=75\left(x-\frac{1}{2}\right)\\ & \iff 15x=\frac{75}{2}\\ & \iff x=\frac{5}{2}\text{ hrs}\end{array}$$
So, the theif is overtaken at 5 pm