A train running at 7/11 of its own speed reached a place in 22 hours. How much time could be saved if the train would have run at its own speed ?

Answer: Option B

New speed = $$\frac{7}{11}$$ of usual speed
∴ New time = $$\frac{11}{7}$$ of usual time
So, $$\frac{11}{7}$$ of usual time = 22 hrs
⇒ Usual time :
= $$\frac{22\times 7}{11}$$
= 14 hrs
Hence, time saved = (22 - 14) = 8 hrs