ABC is a right-angled triangle with AB = 6 cm and BC = 8 cm. A circle with center O has been inscribed inside ΔABC. The radius of the circle is

Answer: Option B

According to question,
Given :

AB = 6 cm,         BC = 8 cm
In right angle ΔABC
By using Pythagoras theorem
AC² = AB² + BC²
AC² = 6² + 8²
AC² = 36 + 64
AC² = 100
AC  = 10 cm
In radius
$$\begin{array}{rl}& =\frac{a+b-c}{2}\\ & =\frac{8+6-10}{2}\\ & =\frac{4}{2}\\ & =2cm\end{array}$$