ABC is a triangle. The bisectors of the internal angle ∠B and external angle ∠C intersect at D. If ∠BDC = 50°, then ∠A is

Answer: Option A

According to question,

Given :
∠D = 50°
∠BAC = 2∠BDC (property)
∴ ∠BAC = 2 × 50°
∠BAC = 100°