Q150
ABC is an isosceles triangle where AB = AC which is circumscribed about a circle. If P is the point where the circle touches the side BC, then which of the following is true?
A.
PB = PC
AnswerB.
PB > PC
C.
PB < PC
D.
PB = PC
Answer: Option A
Solution
Answer: Option A
Solution:
here given that = AB = AC
AQ + BQ = AR + RC
we know that
BQ = PB & PC = RC
AQ + PB = AR + PC
also AQ = AR
AR + PB = AR + PC
PB = PC