ABCD is a cyclic quadrilateral Diagonals BD and AC intersect each other at E. If ∠BEC = 128° and ∠ECD = 25°, then, what is the measure of ∠BAC?

Answer: Option D

∠EDC + ∠DCF = ∠CEB
∠EDC + 25° = 128°
∠EDC = 103°
∠EDC = ∠BAC (all angles are equal same sector)
∠BAC = 103°