ABCDE is a regular pentagon. Its sides are extended as shown in the figure. The value of ABC + 2 EGD + 3 BAJ6 = ?

Answer: Option D

∠ABC = 108° {Internal Angle of regular pentagon}
∠EGD = 108° - (∠E + ∠D)
= 108° - (72° + 72°)
= 36°
∠BAJ = 72°
$$\begin{array}{rl}& \frac{\angle \text{ABC}+2\angle \text{EGD}+3\angle \text{BAJ}}{6}\\ & =\frac{{72}^{\circ }+2\times {36}^{\circ }+3\times {72}^{\circ }}{6}\\ & =18^{\circ }+12^{\circ }+36^{\circ }\\ & =66^{\circ }\end{array}$$