An individual is cycling at a speed of 25 km per hour. He catches his predecessor who had started earlier in two hours. What is the speed of his predecessor who had started 3 hours earlier ?

Answer: Option C

The distance covered in two hour,
= 2 × 25 = 50 km
Time taken by first individual = (3h + 2h) = 5h
Then, the speed of predecessor,
= $$\frac{50}{5}$$ = 10 kmph.