Approximately how many times was the total investment in 1995 and 1996 in district B was that of total investment of district A in the same years?

Answer: Option B

Total investment of A
= 2923.1 + 3489.5
= 6412.6
Total investment of B
= 7081.6 + 8352
= 15433.6
∴ Times = $$\frac{15433.6}{6412.6}$$   = 2.4 (Approx)