Calculate the pH of 0.01 M HCl solution

Answer: Option A

HCl is a strong acid and it dissociates into ions completely.
HCl (aq) 0.01 M → H⁺ (0.01 M) + Cl⁻ (0.01 M)
[H⁺ (aq)] = 0.01 M = 1 × 10^-2
pH = - log₁₀ [H⁺ (aq)]
pH= - log₁₀ [1 × 10^-2]
therefore pH = 2