Q12
Consider the differential equation d^2 y ( t ) d t^2 + 2 dy ( t ) dt + y ( t ) = ( t ) with . y ( t ) |_ t = 0 = - 2 and . dy dt |_ t = 0 = 0. The numerical value of . dy dt |_ t = 0 is
Consider the differential equation with and
The numerical value of is
The numerical value of is
A.
-2
B.
-1
C.
0
D.
1
AnswerAnswer: Option D
Solution
Answer: Option D
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