Q114
Consider the following code: #include int get_min(int a, int b) if(a<b) return a; return b; int minimum_time_required(int reach[][3],int spent[][4], int *entry, int *exit, int n) int t1[n], t2[n],i; t1[0] = entry[0] + spent[0][0]; t2[0] = entry[1] + spent[1][0]; for(i = 1; i < n; i++) t1[i] = get_min(t1[i-1]+spent[0][i], t2[i-1]+reach[1][i-1]+spent[0][i]); __________; return get_min(t1[n-1]+exit[0], t2[n-1]+exit[1]); Which of the following lines should be inserted to complete the above code?
A.
t2[i] = get_min(t2[i-1]+spent[1][i], t1[i-1]+reach[0][i-1]+spent[1][i])
AnswerB.
t2[i] = get_min(t2[i-1]+spent[1][i], t1[i-1]+spent[1][i])
C.
t2[i] = get_min(t2[i-1]+spent[1][i], t1[i-1]+reach[0][i-1])
D.
none of the mentioned
Answer: Option A
Solution
Answer: Option A
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