Q229
Consider the following recursive implementation of the rod cutting problem: #include #include int max_of_two(int a, int b) if(a > b) return a; return b; int rod_cut(int *prices, int len) int max_price = INT_MIN; // INT_MIN is the min value an integer can take int i; if(len <= 0 ) return 0; for(i = 0; i < len; i++) max_price = max_of_two(_____________); // subtract 1 because index starts from 0 return max_price; int main() int prices[]=2, 5, 6, 9, 9, 17, 17, 18, 20, 22,len_of_rod = 10; int ans = rod_cut(prices, len_of_rod); printf("%d",ans); return 0; Complete the above code.
A.
max_price, prices[i] + rod_cut(prices,len - i - 1)
AnswerB.
max_price, prices[i - 1].
C.
max_price, rod_cut(prices, len - i - 1)
D.
max_price, prices[i - 1] + rod_cut(prices,len - i - 1)
Answer: Option A
Solution
Answer: Option A
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