Consider the following type definition. typedef char x[10]; x myArray[5]; What will sizeof(myArray) be ? (Assume one character occupies 1 byte)

Answer: Option C

In this case, the type definition typedef char x[10]; creates a new type x, which is an array of 10 characters. Then, an array of 5 elements of type x is declared as x myArray[5];.

To calculate the size of myArray, you can multiply the size of one element (sizeof(x)) by the number of elements (5):

sizeof(myArray) = sizeof(x) * 5

Since each element x is an array of 10 characters, and assuming each character occupies 1 byte, the size of x is 10 bytes. Therefore:

sizeof(myArray) = 10 bytes * 5 = 50 bytes

So, sizeof(myArray) will be 50 bytes.