Determine Output: void main() static char *s[] = "black", "white", "yellow", "violet"; char **ptr[] = s+3, s+2, s+1, s, ***p; p = ptr; ++p; printf("%s",*--*++p + 3);

Answer: Option D

In this problem we have an array of char pointers "s" pointing to start of 4 strings. Then we have ptr which is a pointer to a pointer of type char and a variable p which is a pointer to a pointer to a pointer of type char. p holds the initial value of ptr, i.e. p = s+3. The next statement increment value in p by 1 , thus now value of p = s+2. In the printf statement the expression is evaluated as follows: *++p causes gets value s+1 then the pre decrement is executed and we get s+1-1 = s which is pointing to the word "black". The indirection operator now gets the value from the array of s and adds 3 to the starting address. The string is printed starting from this position. Thus, the output is 'ck'.