Determine output: public class Test int a = 10; public void method(int a) a += 1; System.out.println(++a); public static void main(String args[]) Test t = new Test(); t.method(3);

Answer: Option B

Here's an explanation of the code:

1. The class Test is defined with an instance variable a initialized to 10.
2. The method method is defined within the Test class, which takes an integer parameter a.
3. Inside the method method, the local variable a shadows the instance variable a because they have the same name.
4. The value of the local variable a is incremented by 1 using the += operator, making it 4.
5. The value of the local variable a is then incremented again using the pre-increment operator ++, making it 5.
6. The value of the local variable a (which is 5) is printed using System.out.println().
7. In the main method, an instance of the Test class is created.
8. The method method is invoked on the t object with the argument 3.
9. This triggers the execution of the method method, which prints 5 as explained above.

Therefore, the output of the code is 5. Thus, option B is the correct answer.