Determine output: void main() int i=0, j=1, k=2, m; m = i++ || j++ || k++; printf("%d %d %d %d", m, i, j, k);

Answer: Option B

In this C program, the expression i++ || j++ || k++ involves the logical OR (||) operator. Here's how it works:

- It evaluates from left to right.
- It stops evaluating as soon as it finds a true condition because in a logical OR operation, if one operand is true, the result is true.

Let's break it down step by step:
- i is initially 0. i++ returns 0 (post-increment), but it increments i to 1.
- j is initially 1. j++ returns 1 (post-increment), and it increments j to 2.
- k is initially 2. k++ returns 2 (post-increment), and it increments k to 3.

Now, the expression is evaluated:
- 0 || 1 is true because one of the operands is true.
- Since the result is true, the evaluation stops.

After the evaluation:
- m is assigned the value 1 because the result is true.
- i is 1 because i was incremented during the evaluation.
- j is 2 because j was incremented during the evaluation.
- k is 2 because k was not incremented further.

Therefore, the output of the printf statement is 1 1 2 2, which corresponds to Option B.