Dev can hit a target 3 times in 6 shots pawan can hit the target 2 times in 6 shots and Lakhan can hit the target 4 times in 4 shots. What is the probability that at least 2 shots hit the target -

Answer: Option A

Probability of hitting the target:
Dev can hit target ⇒ $$\frac{3}{6}$$ =$$\frac{1}{2}$$
Lakhan can hit target =$$\frac{4}{4}$$  = 1
Pawan can hit target = $$\frac{2}{6}$$  = $$\frac{1}{3}$$
Required probability that at least 2 shorts hit target
$$\begin{array}{rl}& =\frac{1}{2}\times \frac{2}{3}+\frac{1}{2}\times \frac{1}{3}+\frac{1}{2}\times \frac{1}{3}\\ & =\frac{1}{3}+\frac{1}{6}+\frac{1}{6}\\ & =\frac{4}{6}\\ & =\frac{2}{3}\end{array}$$