Does the following MySQL statement belong to the "Inequality condition"? SELECT product_type.name, product.name FROM product_type INNER JOIN Product ON product_type.dept=Product.dept WHERE product_type.name! =’customers_accounts’;

Answer: Option A

This question asks if the given MySQL statement uses an inequality condition.
Let's break down the code:
SELECT product_type.name, product.name - This part selects the "name" column from both the "product_type" and "product" tables.
FROM product_type INNER JOIN Product ON product_type.dept=Product.dept - This performs a join between the two tables based on the "dept" column, meaning it combines rows from both tables where the "dept" values match.
WHERE product_type.name! =’customers_accounts’ - This is the key part of the code. It uses the ! = symbol, which means "not equal to". This is an inequality condition.
Therefore, the answer is Option A: Yes.
The statement uses an inequality condition because it filters the results to exclude rows where "product_type.name" equals "customers_accounts".