Farah got married 8 years ago, Today her age is 12/7 times her age at the time of her marriage. At present her daughter's age is one-sixth of her age. What was her daughter's age 3 years ago ?

Answer: Option B

Let Farah's age 8 years ago be x years.
Then , her present age = (x + 8)
$$\begin{array}{rl}& \therefore x+8=\frac{9}{7}x\\ & \Rightarrow 7x+56=9x\\ & \Rightarrow 2x=56\\ & \Rightarrow x=28\end{array}$$
∴ Farah's age now
= (x + 8) years
= (28 + 8) years
= 36
Her daughter's age now
=$$\left(\frac{1}{6}\times 36\right)$$   years
= 6 years
Her daughter's age 3 years ago
= (6 - 3) years
= 3 years