Fill in the blank to complete the code. #include int main() int coins[10]=1,3,4,lookup[100000]; int i,j,tmp,num_coins = 3,sum=100; lookup[0]=0; for(i = 1; i <= sum; i++) int min_coins = i; for(j = 0;j < num_coins; j++) tmp = i - coins[j]; if(tmp < 0) continue; if(lookup[tmp] < min_coins) ______________; lookup[i] = min_coins + 1; printf("%d",lookup[sum]); return 0;

Answer: Option B