Find the angle of elevation of the sun when the shadow of a pole of 18 m height is 6 3 m long?

Answer: Option B

Let RQ be the pole and PQ be the shadow
Given that RQ = 18 m and PQ = $$6\sqrt{3}$$ m
Let the angle of elevation, ∠RPQ = $$\theta$$
$$\begin{array}{rl}& \text{From the right}\Delta PQR,\\ & \text{tan}\theta =\frac{RQ}{PQ}\\ & =\frac{18}{6\sqrt{3}}\\ & =\frac{3}{\sqrt{3}}\\ & =\sqrt{3}\\ & \Rightarrow \theta ={\tan }^{-1}\left(\sqrt{3}\right)=60^{\circ }\end{array}$$