Vidyalelo
Aptitude · Q18

Coordinate Geometry

Competitive Exams · Aptitude · question 18

Q18

Find the equation of a circle whose diameter has end points (4, 3) and (-2, 1).

A.
x2 + y2 - 2x - 4y = 3
B.
x2 + y2 - 2x - 4y = 5
Answer
C.
x2 + y2 - 6x + 2y = 3
D.
x2 + y2 - 2x + 4y = 5

Answer: Option B

Solution

Answer: Option B
Solution:
Go through option,
Points (4, 3) and (-2, 1) will satisfy the equation from option B, x2 + y2 - 2x - 4y = 5