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Aptitude · Q133

Problems On H.C.F And L.C.M

Competitive Exams · Aptitude · question 133

Q133

Find the least multiple of 23, which when divided by 18, 21 and 24 leaves remainders 7, 10 and 13 respectively = ?

A.
3002
B.
3013
Answer
C.
3024
D.
3036

Answer: Option B

Solution

Answer: Option B
Solution:
Here (18 - 7) = 11, (21 - 10) = 11, (24 - 13) = 11
LCM of 18, 21 and 24 is 504
Let the required number be 504k - 11
Least value of k for which (504k - 11) is divisible by 23 is k = 6
∴ Required number
= 504 × 6 - 11
= 3024 - 11
= 3013