Find the output of the following code. #include using namespace std; void crossP(int A[], int B[], int cross[]) cross[0] = A[1] * B[2] - A[2] * B[1]; cross[1] = A[0] * B[2] - A[2] * B[0]; cross[2] = A[0] * B[1] - A[1] * B[0]; int main() int A[] = 1, 2, 4 ; int B[] = 2, 3, 2 ; int cross[3]; crossP(A, B, cross); for (int i = 0; i < 3; i++) cout << cross[i] << " "; return 0;

Answer: Option D