For a triangle base is 6 3 cm and two base angles are 30° and 60°. Then height of the triangle is

Answer: Option B

According to question,
Given : ABC is a right angle triangle

BC = 6$$\sqrt{3}$$
∴ sin 30° = $$\frac{P}{H}$$ = $$\frac{AB}{6\sqrt{3}}$$
AB = 3$$\sqrt{3}$$

sin 60° = $$\frac{P}{H}$$ = $$\frac{AN}{AB}$$
$$\frac{\sqrt{3}}{2}$$ = $$\frac{AN}{3\sqrt{3}}$$
AN = $$\frac{9}{2}$$
AN = 4.5 cm